A can contains a mixture of two liquids A and B in the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many litres of liquid A was contained by the can initially ?
Let the initial quantity of the mixture be x liters.
The ratio of A to B is 7:5, so the amount of A initially = (7/12) × x.
After removing 9 liters, the new amount of A becomes (7/12) × (x - 9).
After adding 9 liters of B, the new ratio becomes 7:9.
Solving this equation gives x = 36, so the initial amount of A = (7/12) × 36 = 21 liters.
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