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    A boat can cover 120 km upstream and back in a total of 30 hours, and 25 km upstream and 40 km downstream in a total of 7 hours. How much distance wil
    Question

    A boat can cover 120 km upstream and back in a total of 30 hours, and 25 km upstream and 40 km downstream in a total of 7 hours. How much distance will the boat cover in 16 hours in still water?

    A.

    200 km

    B.

    180 km

    C.

    175 km

    D.

    225 km

    Correct option is A

    Given:
    The boat covers 120 km upstream and back downstream in 30 hours.
    The boat covers 25 km upstream and 40 km downstream in 7 hours.
    Formula Used:
    Speed of boat in still water: b (km/h)
    Speed of the current: c (km/h)
    Speed of the boat upstream, U = b − c (km/h)
    Speed of the boat downstream, D = b + c (km/h) 
    Solution: 
    120U+120D=30 ....(i) 25U+40D=7 ....(ii) \frac{120}{\text{U}} + \frac{120}{\text{D}} = 30 \space .... \text {(i)} \\ \ \\ \frac{25}{\text{U}} + \frac{40}{\text{D}} = 7 \space .... \text{(ii)} \\ \ \\
    multiplying by 3 in equation (ii) and then subtracting both (i) and (ii) .
    120U+120D=30 ....(i) 75U120D=21 ....(ii)  we get 45U=9\frac{120}{\text{U}} + \frac{120}{\text{D}} = 30 \space .... \text {(i)} \\ \ \\ \underline{ -\frac{75}{\text{U}} - \frac{120}{\text{D}} = -21} \space .... \text{(ii)} \\ \ \\ \text { we get} \space \frac{ 45}{\text{U}} = 9
    Now Upstream, U ( b - c ) = 5 km/h 
    So, Downstream, D ( b + c )  = 20 km/h 
    So the distance cover in 16 hours by boat  = 20+52×16=200km\frac{ 20 + 5}{2} \times 16 = 200 km ​

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