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    90 liters mixture contains juice and water in the ratio of 5 : 4 respectively. If 36 liters mixture taken out and same quantity of water added in the
    Question


    90 liters mixture contains juice and water in the ratio of 5 : 4 respectively. If 36 liters mixture taken out and same quantity of water added in the remaining mixture, then find ratio of initial quantity of water to quantity of water in resulting mixture.

    A.

    2 : 5

    B.

    1 : 1

    C.

    2 : 3

    D.

    3 : 5

    E.

    1 : 2

    Correct option is C

    Initial quantity of juice = 90 ×5/9=50 liters
    So, initial quantity of water = 90 – 50 = 40 liters
    Quantity of water in resulting mixture = 40 – 36 ×4/9+36 = 60 liters
    Required ratio = 40 : 60 = 2 : 3

    Exam Hall Method: 

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