​$$6 × \frac{1}{7}÷\frac{3}{7} + (\frac{45}{24}-\frac{2}{3}+\frac{7}{6}×\frac{2}{7})$$​​

Correct option is A

Given: 

$$6 × \frac{1}{7}÷\frac{3}{7} + (\frac{45}{24}-\frac{2}{3}+\frac{7}{6}×\frac{2}{7})$$  

Concept Used:

Solution: 

$$6 × \frac{1}{7}÷\frac{3}{7} + (\frac{45}{24}-\frac{2}{3}+\frac{7}{6}×\frac{2}{7}) \\\ \\$$ 

= $$6 × \frac{1}{7}\times\frac{7}{3} + (\frac{15}{8}-\frac{2}{3}+\frac{1}{3})$$

=  2 +  $$\frac{15 }{8} + \frac{- 2+1}{3}$$ 

= $$2 + \frac{15}{8} - \frac{1}{3}$$ 

= $$\frac{48 + 45 - 8}{24}$$ 

= $$\frac{85}{24}$$​