What is value of $$21\times 6\div 18-3 \div2+3-3\div(9\ \text{of}\ 3)\times 9+3\div(18\ \text{of}\ 3)\times 6?$$​​

Correct option is A

Given :

$$21\times 6\div 18-3 \div2+3-3\div(9\text{ of }3)\times 9+3\div(18\text{ of }3)\times 6$$ 

Concept Used:

​$$\begin{array}{|l|l|}\hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} & [\,], \{\,\}, (\,) \\\hline\text{Orders, of} & ^x \, (\text{power}), \, \sqrt{} \, (\text{root}), \, \text{of} \\\hline\text{Division} & \div \\\hline\text{Multiplication} & \times \\\hline\text{Addition} & + \\\hline\text{Subtraction} & - \\\hline\end{array}$$​​
Solution :

=$$7-\frac{3}{2}+3-\frac{3}{27}\times 9+\frac{3}{54}\times 6$$​​

​$$= 7-\frac{3}{2}+3-1+\frac{1}{3}$$​​

​$$= \frac{47}{6}$$​​
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