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The value of [3÷2×(7−2)]−(3÷2of6)−2 [3 ÷ 2 × (7 - 2)] - (3 ÷ 2 of 6) - 2[3÷2×(7−2)]−(3÷2of6)−2​ is:
Question

The value of [3÷2×(7−2)]−(3÷2of6)−2 [3 ÷ 2 × (7 - 2)] - (3 ÷ 2 of 6) - 2​ is:

A.

4.75

B.

6.25

C.

5.75

D.

5.25

Correct option is D

Given

Expression = [3 ÷ 2 × (7 - 2)] - (3 ÷ 2 of 6) - 2
Solution:

[3÷2×(7−2)]−(3÷2 of 6)−2 =[3÷2×5]−(3÷(2×6))−2 =[32×5]−(3÷12)−2 =152−14−2 =304−14−2 =294−2 =294−84 =214=5.25[3 \div 2 \times (7-2)]-(3 \div 2 \text{ of }6)-2\\\ \\=[3 \div 2 \times 5]-(3 \div (2 \times 6))-2\\\ \\=\left[\frac{3}{2}\times5\right]-\left(3\div12\right)-2\\\ \\=\frac{15}{2}-\frac14-2\\\ \\=\frac{30}{4}-\frac14-2\\\ \\=\frac{29}{4}-2\\\ \\=\frac{29}{4}-\frac84\\\ \\=\frac{21}{4} = 5.25\\[8pt]​

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