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    ​13​\frac{1}{3}​31​ of a commodity is sold at the rate of 15% profit, 14\frac{1}{4}41​ is sold at the rate of 20% profit and the rest is sol
    Question

    13​\frac{1}{3} of a commodity is sold at the rate of 15% profit, 14\frac{1}{4} is sold at the rate of 20% profit and the rest is sold at the rate of 24% profit. If a total profit of ₹62 is earned, then find the cost price of the commodity.

    A.

    ₹310

    B.

    ₹325

    C.

    ₹300

    D.

    ₹320

    Correct option is A

    Given:

    13\frac{1}{3}of the commodity sold at 15% profit

    14\frac{1}{4} at 20% profit

    Remaining at 24% profit

    Total profit = ₹62

    Solution:
    Let total cost price = ₹x
    Then profits from each part:

    13x×15100\frac{1}{3}x \times \frac{15}{100}​​

    14x×20100\frac{1}{4}x \times \frac{20}{100}​​

    Remaining part = 11314=5121 - \frac{1}{3} - \frac{1}{4} = \frac{5}{12}​​

    512x×24100→ \frac{5}{12}x \times \frac{24}{100}​​

    Sum of all profits = ₹62

    13x×15100+14x×20100+512x×24100=62\frac{1}{3}x \times \frac{15}{100} + \frac{1}{4}x \times \frac{20}{100} + \frac{5}{12}x \times \frac{24}{100} = 62​​

    x(15300+20400+1201200)=62x \left( \frac{15}{300} + \frac{20}{400} + \frac{120}{1200} \right) = 62​​

    x(120+120+110)=62x \left( \frac{1}{20} + \frac{1}{20} + \frac{1}{10} \right) = 62​​

    x×420=62x \times \frac{4}{20} = 62

    x×15=62x \times \frac{1}{5} = 62

    x = 62×5=62 \times 5 = ​310 (Cost Price of the commodity)

    Alternate Method:

    Total cost price = Rs.12

    1Part                2 part              3 Part

    13×1214×125\frac 13\times 12 \quad \quad \quad \frac 14\times 12 \quad \quad \quad 5​             

    4                      3                      5

    15%                20%                  24% (profit)

    Overall Profit %=60+60+12012\frac{60+60+120}{12} = 20%   

    Sum of all profits = ₹62​

    Cost Price of the commodity = 62×5=62 \times 5 =  310​

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