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Which two signs should be interchanged to make the given equation correct?335 × 5 ÷ 7 + 65 − 213 = 321
Question

Which two signs should be interchanged to make the given equation correct?
335 × 5 ÷ 7 + 65 − 213 = 321

A.

+ and =

B.

÷ and ×

C.

÷ and −

D.

+ and −

Correct option is B

Logic: interchange mathematical operators and solve as per BODMAS rule.
Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}​​
Check option A,​​+ and =​
Given:
335 × 5 ÷ 7 + 65 − 213 = 321
After interchanging,
335 × 5 ÷ 7 = 65 − 213 + 321
Here, 5 is perfectly not divisible by 7.
So, its not correct option.
Check option B, ​​÷ and ×​
Given:
335 × 5 ÷ 7 + 65 − 213 = 321
After interchanging,
335 ÷ 5 × 7 + 65 − 213 = 321
67 × 7 + 65 − 213 = 321
469 + 65 − 213 = 321
321=321
So, its correct option.
Check option C, ​​÷ and −
Given:
335 × 5 ÷ 7 + 65 − 213 = 321
After interchanging,
335 × 5 - 7 + 65 ÷ 213 = 321
Here, 65 is perfectly not divisible by 213.
So, its not correct option.
Check option D,​​+ and −​
Given:
335 × 5 ÷ 7 + 65 − 213 = 321
After interchanging,
335 × 5 ÷ 7 - 65 + 213 = 321
Here, 5 is perfectly not divisible by 7.
So, its not correct option.
Thus, correct option is (b).

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