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    Which two signs should be interchanged to make the following equation correct?33 + 4 × 21 ÷ 3 − 17 = 122
    Question

    Which two signs should be interchanged to make the following equation correct?
    33 + 4 × 21 ÷ 3 − 17 = 122

    A.

    – and ×

    B.

    ÷ and –

    C.

    + and ×

    D.

    + and –

    Correct option is C

    Given:
    33 + 4 × 21 ÷ 3 − 17 = 122
    Logic: interchange mathematical operators and solve as per BODMAS rule.
    Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}​​
    Check option A,– and ×
    Given:
    33 + 4 × 21 ÷ 3 − 17 = 122
    After interchanging,
    33 + 4 - 21 ÷ 3 × 17 = 122
    37 - 21 × 17 = 122
    37 - 357 = 122
    -320≠122
    So, its not correct option.
    Check option B, ÷ and –
    Given:
    33 + 4 × 21 ÷ 3 − 17 = 122
    After interchanging,
    33 + 4 × 21 - 3 ÷ 17 = 122
    Here, 3 is perfectly not divisible by 17.
    So, its not correct option.
    Check option C,+ and ×
    Given:
    33 + 4 × 21 ÷ 3 − 17 = 122
    After interchanging,
    33 × 4 + 21 ÷ 3 − 17 = 122
    132 + 7 − 17 = 122
    122=122
    So, its correct option.
    Check option D,+ and –
    Given:
    33 + 4 × 21 ÷ 3 − 17 = 122
    After interchanging,
    33 - 4 × 21 ÷ 3 + 17 = 122
    50 - 4 × 7 = 122
    50 - 28 = 122
    22≠122
    So, its not correct option.
    Thus, correct option is (c).

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