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Which two numbers should be interchanged to make the given equation correct?​72−56+(13+19)×2−95÷5+17=7672 - 56 + (13 + 19) \times 2 - 95 \div 5 + 17 =
Question

Which two numbers should be interchanged to make the given equation correct?

7256+(13+19)×295÷5+17=7672 - 56 + (13 + 19) \times 2 - 95 \div 5 + 17 = 76

(Note: Interchange should be done of the entire number and not individual digits of a given number.)

A.

19 and 5

B.

19 and 17

C.

17 and 56

D.

13 and 17

Correct option is B

Given: 
Form the given options - 
(a) 19 and 5  After interchanging the digit we get following equation- 
7256+(13+5)×295÷19+17=76 7256+18×25+17=76 7256+365+17=76 12561=76 6476 72 - 56 + (13 + 5) \times 2 - 95 \div 19 + 17 = 76 \\ \ \\ 72 - 56 + 18 \times 2 - 5 + 17 = 76 \\ \ \\ 72 - 56 +36 - 5 + 17 = 76 \\ \ \\ 125 - 61 = 76 \\ \ \\ 64\not = 76 \\ \ \\  
(b) 19 and 17 After interchanging the digit we get following equation- 
7256+(13+17)×295÷5+19=76 7256+(30)×219+19=76 7256+6019+19=76 15175=76 76=76 72 - 56 + (13 + 17) \times 2 - 95 \div 5 + 19 = 76 \\ \ \\ 72 - 56 + (30) \times 2 - 19 + 19 = 76 \\ \ \\ 72 - 56 + 60 - 19 + 19 = 76 \\ \ \\ 151 - 75 = 76 \\ \ \\ 76 = 76 \\ \ \\
Thus, the correct answer is (b).

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