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    Which two numbers should be interchanged to make the following equation correct?29 – 19 + 25 × 87 ÷ 44 = 100
    Question

    Which two numbers should be interchanged to make the following equation correct?
    29 – 19 + 25 × 87 ÷ 44 = 100

    A.

    19 and 25

    B.

    44 and 87

    C.

    29 and 44

    D.

    87 and 29

    Correct option is C

    Given: 29 – 19 + 25 × 87 ÷ 44 = 100
    Operation preference wiseSymbolBrackets[],,()Orders, of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}
    After interchanging the  number in the given equation will be: 
    Option (a): 19 and 25
    29 – 25 + 19 × 87 ÷ 44 = 100
    ​​29 – 25 + 19 × 2 = 100
    ​​​29 – 25 + 38 = 100
    29 + 38 - 25 = 100
    67 - 25 = 100
    42 \neq​100
    It is incorrect.
    Option (b): 44 and 87
    29 – 19 + 25 × 44 ÷ 87 = 100
    ​​29 – 19 + 25 × 0.50 = 100
    ​​​29 – 19 + 12.5 = 100
    29 + 12.5 - 19 = 100
    41.5 - 19 = 100
    22.5 \neq100
    It is incorrect.
    Option (c): 29 and 44
    44 – 19 + 25 × 87 ÷ 29 = 100
    ​44 – 19 + 25 × 3 = 100
    ​​44 – 19 + 75 = 100
    44 + 75 - 19 = 100
    119 -19 = 100
    100 = 100
    It is correct.
    Option (d): 87 and 29
    87 – 19 + 25 × 29 ÷ 44 = 100
    87 – 19 + 25 × 0.65 = 100
    87 – 19 + 16 .25 = 100
    87 + 16.25 - 19 = 100
    103.25 - 19 = 100
    84.25 \neq​ 100
    It is incorrect.
    Thus, the correct option is (c) 29 and 44.

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