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Which two numbers should be interchanged to make the following equation correct?29 – 19 + 25 × 87 ÷ 44 = 100
Question

Which two numbers should be interchanged to make the following equation correct?
29 – 19 + 25 × 87 ÷ 44 = 100

A.

19 and 25

B.

44 and 87

C.

29 and 44

D.

87 and 29

Correct option is C

Given: 29 – 19 + 25 × 87 ÷ 44 = 100
Operation preference wiseSymbolBrackets[],,()Orders, of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}
After interchanging the  number in the given equation will be: 
Option (a): 19 and 25
29 – 25 + 19 × 87 ÷ 44 = 100
​​29 – 25 + 19 × 2 = 100
​​​29 – 25 + 38 = 100
29 + 38 - 25 = 100
67 - 25 = 100
42 \neq​100
It is incorrect.
Option (b): 44 and 87
29 – 19 + 25 × 44 ÷ 87 = 100
​​29 – 19 + 25 × 0.50 = 100
​​​29 – 19 + 12.5 = 100
29 + 12.5 - 19 = 100
41.5 - 19 = 100
22.5 \neq100
It is incorrect.
Option (c): 29 and 44
44 – 19 + 25 × 87 ÷ 29 = 100
​44 – 19 + 25 × 3 = 100
​​44 – 19 + 75 = 100
44 + 75 - 19 = 100
119 -19 = 100
100 = 100
It is correct.
Option (d): 87 and 29
87 – 19 + 25 × 29 ÷ 44 = 100
87 – 19 + 25 × 0.65 = 100
87 – 19 + 16 .25 = 100
87 + 16.25 - 19 = 100
103.25 - 19 = 100
84.25 \neq​ 100
It is incorrect.
Thus, the correct option is (c) 29 and 44.

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