Which one of the following is the oxidation state of oxygen in OF₂ ?

Correct option is A

Explanation:

The correct answer is +2.
In OF₂ (Oxygen Difluoride), oxygen is bonded to two fluorine atoms. Since fluorine is the most electronegative element, it has an oxidation state of -1 in compounds. The sum of the oxidation states in the molecule must equal zero.
Let the oxidation state of oxygen be $x$:
$x+2(-1)=0$
$x=+2$
Thus, the oxidation state of oxygen in OF₂ is +2.

Information Booster:
● Oxygen typically has an oxidation state of -2 in most compounds.
● In peroxides (like H₂O₂), oxygen has an oxidation state of -1.
● Fluorine always exhibits an oxidation state of -1 due to its electronegativity.
● OF₂ is a rare example where oxygen has a positive oxidation state.
● OF₂ is a highly reactive compound used as an oxidizing agent.