Correct option is B
The correct answer is (B) Ethyne
Explanation:
Ethyne (acetylene) undergoes hydration in the presence of mercury(II) sulfate (HgSO₄) and sulfuric acid (H₂SO₄) to produce acetaldehyde (CH₃CHO). This reaction involves a Markovnikov addition, where the water adds to the alkyne, resulting in the formation of an aldehyde.
Information Booster:
The reaction is known as hydroboration-oxidation of alkynes.
In the presence of HgSO₄ and H₂SO₄, Ethyne undergoes Markovnikov's rule for the addition of water.
The product formed is acetaldehyde, a simple aldehyde.
This reaction is commonly used in industrial processes for producing aldehydes.
Ethyne (acetylene) is a simple alkyne that readily reacts with water under acidic conditions.
The reaction occurs through an intermediate enol, which tautomerizes to form the aldehyde.
Additional Information:
Hex-2-yne: Under the same conditions, it produces a ketone rather than an aldehyde.
But-2-yne: Similarly, this alkyne produces a ketone and does not yield an aldehyde.
Propyne: Like other alkynes, it also produces a ketone rather than an aldehyde under these conditions.
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