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    Which of the following options is the closest approximate value which will come in place of question mark (?) in the following equation?​104.96+120.96
    Question

    Which of the following options is the closest approximate value which will come in place of question mark (?) in the following equation?

    104.96+120.96+103.1612.89×2.04+124.93÷5.1=?104.96 + 120.96 + 103.16 – 12.89 × 2.04 + 124.93 \div 5.1 = ?​​

    A.

    328

    B.

    334

    C.

    340

    D.

    330

    Correct option is A

    Given:

    104.96+120.96+103.1612.89×2.04+124.93÷5.1104.96 + 120.96 + 103.16 – 12.89 × 2.04 + 124.93 \div 5.1

    Formula Used:

    Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}

    Solution:

    104.96+120.96+103.1612.89×2.04+124.93÷5.1104.96 + 120.96 + 103.16 – 12.89 × 2.04 + 124.93 \div 5.1​​

    104.96+120.96+103.1626+25104.96 + 120.96 + 103.16 – 26 + 25​​

    =105+121+10326+25= 105 +121 + 103 -26+25​​

    = 328

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