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    Which of the following interchanges of numbers would make the given equation correct? 7×10÷6+3-2=10
    Question

    Which of the following interchanges of numbers would make the given equation correct?
    7×10÷6+3-2=10

    A.

    6, 10

    B.

    2, 6

    C.

    3, 7

    D.

    3, 6

    Correct option is C

    Given:
    7×10÷6+3-2=10
    Solution:
    (a) Interchange 6,10
    =7×6÷10+3-2
    =42÷10+3-2
    =4.2+3-2
    7.2-2= 5.2 is not equal to 10 (False)
    (b) Interchange 2,6
    =7×10÷2+3-6
    =70÷2+3-6
    =35+3-6
    =38-6 = 32 is not equal to 10 (False)
    (c) Interchange 3,7
    =3×10÷6+7-2
    =30÷6+7-2
    =5+7-2
    =12-2= 10 is equal to 10 (True)
    (d) Interchange 3,6
    =7×10÷3+6-2
    =70÷3+6-2
    = 23.33+6-2
    =29.33-2
    =27.33 is not equal to 10
    Thus the correct answer is (C)

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