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Which of the following interchanges of numbers would make the given equation correct? 7×10÷6+3-2=10
Question

Which of the following interchanges of numbers would make the given equation correct?
7×10÷6+3-2=10

A.

6, 10

B.

2, 6

C.

3, 7

D.

3, 6

Correct option is C

Given:
7×10÷6+3-2=10
Solution:
(a) Interchange 6,10
=7×6÷10+3-2
=42÷10+3-2
=4.2+3-2
7.2-2= 5.2 is not equal to 10 (False)
(b) Interchange 2,6
=7×10÷2+3-6
=70÷2+3-6
=35+3-6
=38-6 = 32 is not equal to 10 (False)
(c) Interchange 3,7
=3×10÷6+7-2
=30÷6+7-2
=5+7-2
=12-2= 10 is equal to 10 (True)
(d) Interchange 3,6
=7×10÷3+6-2
=70÷3+6-2
= 23.33+6-2
=29.33-2
=27.33 is not equal to 10
Thus the correct answer is (C)

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