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Which of the following interchanges of numbers would make the given equation correct? 2 × 10 ÷ 8 + 6 – 4 = 9
Question

Which of the following interchanges of numbers would make the given equation correct?
2 × 10 ÷ 8 + 6 – 4 = 9

A.

2, 8

B.

6, 8

C.

9, 10

D.

2, 4

Correct option is D

Given:
2 × 10 ÷ 8 + 6 - 4 = 9
Logic:
Let's check all the options
A) 2, 8
Apply the changes
=> 8 ×10 ÷ 2+ 6 - 4 = 9
Use BODMAS rule
=> 8 × 5+ 6 - 4 = 9
=> 40 + 6- 4 = 9
=>46 - 4= 9
=> 42 = 9, false
B) 6, 8
Apply the changes
=> 2 ×10 ÷ 6+ 8 - 4 = 9
Use BODMAS rule
=> 2 × 1.66 + 8 - 4 = 9
=> 3.33 + 8- 4 = 9
=> 11.33 - 4= 9
=> 7.33 = 9, false
C) 9,10
Apply the changes
=> 2 ×9 ÷ 8+ 6 - 4 = 10
Use BODMAS rule
=> 2 × 1.125+ 6 - 4 = 10
=> 2.25 + 6- 4 = 10
=> 8.25 - 4= 10
=> 4.25 = 10, false
D) 2, 4
Apply the changes
=> 4 ×10 ÷ 8+ 6 - 2 = 9
Use BODMAS rule
=> 4 × 1.25+ 6 - 2 = 9
=>5 + 6- 2= 9
=>11- 2 = 9
=> 9 = 9, true
So, the numbers 2, 4 are interchanged to get the correct answer. 
Hence, the correct answer is (d).

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