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    Which of the following interchanges of numbers would make the given equation correct? 2 × 10 ÷ 8 + 6 – 4 = 9
    Question

    Which of the following interchanges of numbers would make the given equation correct?
    2 × 10 ÷ 8 + 6 – 4 = 9

    A.

    2, 8

    B.

    6, 8

    C.

    9, 10

    D.

    2, 4

    Correct option is D

    Given:
    2 × 10 ÷ 8 + 6 - 4 = 9
    Logic:
    Let's check all the options
    A) 2, 8
    Apply the changes
    => 8 ×10 ÷ 2+ 6 - 4 = 9
    Use BODMAS rule
    => 8 × 5+ 6 - 4 = 9
    => 40 + 6- 4 = 9
    =>46 - 4= 9
    => 42 = 9, false
    B) 6, 8
    Apply the changes
    => 2 ×10 ÷ 6+ 8 - 4 = 9
    Use BODMAS rule
    => 2 × 1.66 + 8 - 4 = 9
    => 3.33 + 8- 4 = 9
    => 11.33 - 4= 9
    => 7.33 = 9, false
    C) 9,10
    Apply the changes
    => 2 ×9 ÷ 8+ 6 - 4 = 10
    Use BODMAS rule
    => 2 × 1.125+ 6 - 4 = 10
    => 2.25 + 6- 4 = 10
    => 8.25 - 4= 10
    => 4.25 = 10, false
    D) 2, 4
    Apply the changes
    => 4 ×10 ÷ 8+ 6 - 2 = 9
    Use BODMAS rule
    => 4 × 1.25+ 6 - 2 = 9
    =>5 + 6- 2= 9
    =>11- 2 = 9
    => 9 = 9, true
    So, the numbers 2, 4 are interchanged to get the correct answer. 
    Hence, the correct answer is (d).

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