Which of the following interchanges of numbers (not digits) would make the given equation correct?

​$$\frac{480÷0.3×5+500}{190+9×27÷1.6}=2$$​​

Given:  $$\frac{480÷0.3×5+500}{190+9×27÷1.6}=2$$ 

Let's check the options;

Option (a); ​0.3 and 1.6

 $$\frac{480÷1.6×5+500}{190+9×27÷0.3}=2\\ \ \\ \frac{300×5+500}{190+9×90}= 2 \\ \ \\ \frac{1500+500}{190+810}= 2 \\ \ \\ \frac{2000}{1000}= 2\\ \ \\ \bf2= 2$$

Thus, correct option is (a).