Correct option is A
To check divisibility by 2, we only need to check if the last digit is even. Both 8448 and 9636 have even last digits, so they are divisible by 2.
To check divisibility by 3, we need to add up the digits of the number and see if the sum is divisible by 3. The sum of the digits of 8448 is 24, which is divisible by 3, so 8448 is divisible by 3. Similarly, the sum of the digits of 9636 is 24, so 9636 is divisible by 3.
To check divisibility by 11, we can use the alternating sum method. This involves subtracting the digits in the even places from the digits in the odd places, and then seeing if the result is divisible by 11. For 8448, the alternating sum is (8 - 4) + (4 - 8) + (4 - 4) = 0, which is divisible by 11. For 9636, the alternating sum is (9 - 6) + (6 - 3) + (3 - 6) = 0, which is divisible by 11.
Therefore, the only two numbers that are divisible by 2, 3, and 11 are 8448 and 9636. So the correct option is (a) A and D.