Which least number when divided by 12, 15, 20 and 54 leaves a remainder 8 in each case?

​A number when divided by 12, 15, 20, 54 leaves a remainder of 8 in each case.

A number N that leaves the same remainder R when divided by multiple divisors is of the form:

N = LCM of the divisors + R

L.C.M of 12, 15, 20, 54 = 540

So, least number will be = 540 + 8 =548

Thus, 548 is the least number when divided by 12, 15, 20, 54 leaves 8 as a remainder.