Which least number should be added to 10100, so that the sum is exactly divisible by 49?

Correct option is C

Solution:

Divide 10100 by 49:

49 × 206 = 10094

Remainder:

10100 - 10094 = 6

Least number to be added:

49 - 6 = 43

So,

10100 + 43 = 10143

which is exactly divisible by 49.

Required least number = 43