Correct option is D
From Newton's third equation of motion v² = u² - 2as------(When a is negative)
When car is stop then v = 0
Stopping Distance:
The stopping distance of a car is directly proportional to the square of its speed:
d ∝ v2
This relationship comes from the work-energy principle, where the kinetic energy of the car (KE = ½.mv2) must be dissipated by the braking force.
Doubling the Speed:
If the speed v is doubled, the stopping distance becomes:
d′=k(2v)2 = 4kv2 = 4d.
