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When 100 balls were equally distributed among students in a class (having strength between 10 and 60), 7 balls remained undistributed. The number of b
Question

When 100 balls were equally distributed among students in a class (having strength between 10 and 60), 7 balls remained undistributed. The number of balls that would remain if there were 125 balls to begin with is

A.

Indeterminable 

B.

1

C.

5

D.

9

Correct option is B

Given:
100 balls are equally distributed among students.
Class strength (number of students) is between 10 and 60.
After distributing, 7 balls remain.
If there were 125 balls instead, how many balls would remain?

Solution:
Step 1: Understand the condition
If 100 balls leave 7 balls remaining, it means:

100 ÷ number of students leaves remainder 7

Let number of students = n

So: 100 mod n = 7 => (100 − 7) = 93 is divisible by n

Therefore: n divides 93 exactly, and
n is between 10 and 60

Step 2: Find divisors of 93 between 10 and 60
Prime factorization of 93 = 3 × 31
So divisors of 93 = 1, 3, 31, 93
From these, only 31 lies between 10 and 60

So the class strength n = 31
Step 3: Now find remainder when 125 balls are distributed among 31 students
125 ÷ 31 = 4 remainder 1

Final Answer:
S. Ans. (B) 1

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