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    When 100 balls were equally distributed among students in a class (having strength between 10 and 60), 7 balls remained undistributed. The number of b
    Question

    When 100 balls were equally distributed among students in a class (having strength between 10 and 60), 7 balls remained undistributed. The number of balls that would remain if there were 125 balls to begin with is

    A.

    Indeterminable 

    B.

    1

    C.

    5

    D.

    9

    Correct option is B

    Given:
    100 balls are equally distributed among students.
    Class strength (number of students) is between 10 and 60.
    After distributing, 7 balls remain.
    If there were 125 balls instead, how many balls would remain?

    Solution:
    Step 1: Understand the condition
    If 100 balls leave 7 balls remaining, it means:

    100 ÷ number of students leaves remainder 7

    Let number of students = n

    So: 100 mod n = 7 => (100 − 7) = 93 is divisible by n

    Therefore: n divides 93 exactly, and
    n is between 10 and 60

    Step 2: Find divisors of 93 between 10 and 60
    Prime factorization of 93 = 3 × 31
    So divisors of 93 = 1, 3, 31, 93
    From these, only 31 lies between 10 and 60

    So the class strength n = 31
    Step 3: Now find remainder when 125 balls are distributed among 31 students
    125 ÷ 31 = 4 remainder 1

    Final Answer:
    S. Ans. (B) 1

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