What will be the day of the week on 08 June 2030?

Odd days in 2000n years = 0 

Odd days:

Each normal year = 1 odd day

Each leap year = 2 odd days

Total odd days = (22 × 1) + (7 × 2) = 22 + 14 = 36 ÷ 7 = 1 remainder  (odd days)

Odd days in 2030 = 3 + 0 + 3 + 2 + 3 + 8 = 19 ÷ 7 = 5 remainder (odd days)

Total odd days =  1 + 5 = 6 

Thus, correct option is (a)

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