Correct option is C
To find the day of the week for 22 October 1979:
Odd days in 1900 (1600 + 300) years = 1 odd days
From 1900 to 1978 = 78 + 19 = 97 odd days
From 1 Jan to 22 Oct 1979: 3 + 0 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 22 = 43
Total odd days: 1 + 97 + 43 = 12 → 141 ÷ 7 = 1 odd days.
22 October 1979: Monday.
Year Type | Odd Days (365 mod 7 = 1) |
Normal Year | 1 odd day |
Leap Year | 2 odd days |
100 Years | 5 odd days |
200 Years | 3 odd days |
300 Years | 1 odd day |
400 Years | 0 odd days |
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