Question

What is the value of

A.


B.


C.


D.

Correct option is A

Given:

(k1k)(k2+1k2)(k4+1k4)(k8+1k8)(k16+1k16)(k32+1k32)(k - \frac{1}{k})(k^2 + \frac{1}{k^2})(k^4 + \frac{1}{k^4})(k^8 + \frac{1}{k^8})(k^{16} + \frac{1}{k^{16}})(k^{32} + \frac{1}{k^{32}})

Solution:

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