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What is the value of x in following equation?  ​8.5−[512−(712+2.8÷x)]×4.25÷(0.2)2=3068.5-[5\frac{ 1}{2}-(7 \frac{1}{2}+2.8÷x)]×4.25÷(0.2)^2=
Question

What is the value of x in following equation?  

8.5[512(712+2.8÷x)]×4.25÷(0.2)2=3068.5-[5\frac{ 1}{2}-(7 \frac{1}{2}+2.8÷x)]×4.25÷(0.2)^2=306  

A.

3.08

B.

3.5

C.

2.5

D.

1.8

Correct option is B

Given:

8.5[512(712+2.8÷x)]×4.25÷(0.2)2=3068.5-[5\frac{ 1}{2}-(7 \frac{1}{2}+2.8÷x)]×4.25÷(0.2)^2=306  

Solution:

[512(712+2.8÷x)]×4.25÷(0.2)2=3068.5-[5\frac{ 1}{2}-(7 \frac{1}{2}+2.8÷x)]×4.25÷(0.2)^2=306 - 8.5  

(- 5.5  + 7.5 + 2.8 ÷x)]4254\frac{425}{4}  = 297.5

 2 + 2.8÷x) = 1190425\frac{1190}{425} 

 2.8÷x  = 11904252\frac{1190}{425} - 2  

2.8 ÷x = 1190850425\frac{1190 - 850}{425} 

2.8÷ x = 340425\frac{340}{425} 

 x = 425×2.8340=3.5\frac{425\times2.8}{340} = 3.5 ​​

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