arrow
arrow
arrow
What is the value of the following expression? ​(24÷3of16)×(45÷98×35)÷(47÷314of314)(24÷3 of \frac{1}{6})×(\frac{4}{5}÷\frac{9}{8}×\frac{3}{5})÷(\frac
Question

What is the value of the following expression?
(24÷3of16)×(45÷98×35)÷(47÷314of314)(24÷3 of \frac{1}{6})×(\frac{4}{5}÷\frac{9}{8}×\frac{3}{5})÷(\frac{4}{7}÷\frac{3}{14} of \frac{3}{14}) ​

A.

579459\frac{579}{459}​​

B.

288175\frac{288}{175}​​

C.

379159\frac{379}{159}​​

D.

363553\frac{363}{553}​​

Correct option is B

Concept Used:

Solution:
(243×16)×(45÷98×35)÷(47÷314×314) =(2412)×(3275)÷(47÷9196) =(24×2)×(3275)÷(1129) =48×3275×9112 =288175\left( \frac{24}{3} \times \frac{1}{6} \right) \times \left( \frac{4}{5} \div \frac{9}{8} \times \frac{3}{5} \right) \div \left( \frac{4}{7} \div \frac{3}{14} \times \frac{3}{14} \right) \\\ \\= \left( \frac{24}{\frac{1}{2}} \right) \times \left( \frac{32}{75} \right) \div \left( \frac{4}{7} \div \frac{9}{196} \right) \\\ \\= \left( 24 \times 2 \right) \times \left( \frac{32}{75} \right) \div \left( \frac{112}{9} \right) \\\ \\= 48 \times \frac{32}{75} \times \frac{9}{112} \\\ \\= \frac{288}{175}​​

Free Tests

Free
Must Attempt

SSC GD PYP (Held on 4 Feb 2025 S1)

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English
Free
Must Attempt

Hindi Section Test 1

languageIcon English
  • pdpQsnIcon20 Questions
  • pdpsheetsIcon40 Marks
  • timerIcon12 Mins
languageIcon English
Free
Must Attempt

SSC GD Constable Full Mock Test 1

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English
test-prime-package

Access ‘SSC CHSL Tier I’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
353k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow