What is the value of the following expression?

​$$103 - [144 \div (12 \times 12) + 5+ 12 \div (6 - 2) + 10]$$​​

Correct option is D

Given:

​$$103 - [144 \div (12 \times 12) + 5+ 12 \div (6 - 2) + 10]$$  

Formula used:

​$$\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​​

Solution:

​$$\begin{aligned}&103 - \left[ \frac{144}{(12 \times 12)} + 5 + \frac{12}{(6 - 2)} + 10 \right] \\&\implies 103 - \left[ \frac{144}{144} + 5 + \frac{12}{4} + 10 \right] \\&\implies 103 - \left[ 1 + 5 + 3 + 10 \right] \\&\implies 103 - 19 = 84\end{aligned}$$ 

Hence, option (d) is correct answer.