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What is the value of [21 + 14 -7 × (91÷ 7 -12) + 42]?
Question

What is the value of [21 + 14 -7 × (91÷ 7 -12) + 42]?

A.

80

B.

50

C.

70

D.

60

Correct option is C

Given:
To find: value of ​​
Concept Used:
BODMAS rule:
Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}​​
Solution:
[21+147×(91÷712)+42]=[21+147×(1312)+42]=[21+147×1+42]=[21+147+42]=[21+147+42]=70[21 + 14 -7 × (91÷ 7 -12) + 42]\\=[21 + 14 -7 × (13 -12) + 42]\\=[21 + 14 -7 × 1 + 42]\\=[21 + 14 -7 + 42]\\=[21 + 14 -7 + 42]\\=70\\​​

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