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    What is the value of [21 + 14 -7 × (91÷ 7 -12) + 42]?
    Question

    What is the value of [21 + 14 -7 × (91÷ 7 -12) + 42]?

    A.

    80

    B.

    50

    C.

    70

    D.

    60

    Correct option is C

    Given:
    To find: value of ​​
    Concept Used:
    BODMAS rule:
    Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}​​
    Solution:
    [21+147×(91÷712)+42]=[21+147×(1312)+42]=[21+147×1+42]=[21+147+42]=[21+147+42]=70[21 + 14 -7 × (91÷ 7 -12) + 42]\\=[21 + 14 -7 × (13 -12) + 42]\\=[21 + 14 -7 × 1 + 42]\\=[21 + 14 -7 + 42]\\=[21 + 14 -7 + 42]\\=70\\​​

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