What is the value of   $$\\\left( \frac{133}{7} + \frac{91}{13} - \frac{216}{36} \right) + \left( \frac{209}{11} - \frac{96}{16} + \frac{45}{5} \right)\\$$  ?​

Correct option is D

Solution:

​$$\\\left( \frac{133}{7} + \frac{91}{13} - \frac{216}{36} \right) + \left( \frac{209}{11} - \frac{96}{16} + \frac{45}{5} \right)\\ \frac{133}{7} = 19, \quad \frac{91}{13} \approx 7, \quad \frac{216}{36} = 6 \\\ \\ \frac{209}{11} = 19, \quad \frac{96}{16} = 6, \quad \frac{45}{5} = 9\\\left( 19 + 7 - 6 \right) + \left( 19 - 6 + 9 \right) \\\left( 19 + 7 - 6 \right) = 20 \\\left( 19 - 6 + 9 \right) = 22\ \\20 + 22 = 42$$​​