What is the sum of the cubes of the natural numbers from 5 to 14?

The numbers are: 5, 6, 7, 8, 9, 10, 11, 12, 13, 14.

Sum of cubes from 1 to n:

​$$\left( \frac{n(n+1)}{2} \right)^2$$​​

Sum of cubes from 1 to 14:

​$$S_{14} = \left( \frac{14(14+1)}{2} \right)^2 = \left( \frac{14 \times 15}{2} \right)^2 = 105^2 = 11025$$​​

Sum of cubes from 1 to 4:

​$$S_4 = \left( \frac{4(4+1)}{2} \right)^2 = \left( \frac{4 \times 5}{2} \right)^2 = 10^2 = 100$$​​

Now,

S(5 to 14) = 11025 − 100 = 10925