Given:
Two-digit numbers from 10 to 50
Formula Used:
Sum of an arithmetic progression: S = n/2 × (first term + last term)
Solution:
The two-digit numbers ≤ 50 are: 10, 11, ..., 50
Number of terms (n) = 41
First term (a) = 10, Last term (l) = 50
Sum = 41/2 × (10 + 50) = 41 × 30 = 1230
English
100 Questions
100 Marks
90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishRoman numerals CXIX, XCIX, CXXI, CIX and CXX can be written in increasing order as
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