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    The difference of squares of two consecutive odd numbers is 88. What is the product of the two numbers?
    Question

    The difference of squares of two consecutive odd numbers is 88. What is the product of the two numbers?

    A.

    480

    B.

    476

    C.

    489

    D.

    483

    Correct option is D

    Given:
    Difference of squares of two consecutive odd numbers = 88
    Formula Used:
    (a+b)2a2=a2+2ab+b2a2(a + b)^2 - a^2 = a^2 + 2ab + b^2 - a^2​​
    Solution:
    Let the two consecutive odd numbers be x and x + 2.
    (x+2)2x2(x + 2)^2 - x^2 ​= 88
    (x2+4x+4)x2(x^2 + 4x + 4) - x^2​ = 88
    4x + 4 = 88
    4x = 84
    x = 21
    The first odd number is 21.
    The consecutive odd number is 21 + 2 = 23.
    Now, find their product.
    Product = 21 × 23 = 483
    Final Answer
    So the correct answer is (d)

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