The difference of squares of two consecutive odd numbers is 88. What is the product of the two numbers?

Correct option is D

Given:
Difference of squares of two consecutive odd numbers = 88
Formula Used:
​$$(a + b)^2 - a^2 = a^2 + 2ab + b^2 - a^2$$​​
Solution:
Let the two consecutive odd numbers be x and x + 2.
$$(x + 2)^2 - x^2$$​= 88
$$(x^2 + 4x + 4) - x^2$$​ = 88
4x + 4 = 88
4x = 84
x = 21
The first odd number is 21.
The consecutive odd number is 21 + 2 = 23.
Now, find their product.
Product = 21 × 23 = 483
Final Answer
So the correct answer is (d)