What is the smallest number which, when divided by 15, 17 and 19, leaves remainder 4, 6 and 8, respectively?
Given:
Given numbers are 15, 17 and 19
Formula Used:
LCM of prime numbers = Product of numbers
Solution:
Difference between divisor and remainder:
15 - 4 = 11
17 - 6 = 11
19 - 8 = 11
Here the difference between divisors and remainders is same in all three cases.
Now LCM of 15, 17 and 19 is
The smallest number giving remainder 4,6 and 8 is 4845 - 11 = 4834
English
80 Questions
160 Marks
60 Mins English English80 Questions160 Marks60 Mins English English20 Questions40 Marks25 Mins English28P3 is divisible by 9. What is the value of P?
How many numbers among 51, 62, 84, 97 are divisible by 9?
28P0 is divisible by 8. Which of the following cannot be the value of P?
What is the remainder when 741 is divided by 9?
How many numbers among 5001, 6003, 7204, 8400 are divisible by 6?
A perfect square number lies between 1700 and 1800 and is divisible by 9. Find that number and its square root.
Which of the following number is divisible by both 3 and 8?
Which of the following number is neither divisible by 4 nor by 9?
Which of the following number is divisible by both 9 and 11?
Suggested Test Series
Suggested Test Series
28P3 is divisible by 9. What is the value of P?
How many numbers among 51, 62, 84, 97 are divisible by 9?
28P0 is divisible by 8. Which of the following cannot be the value of P?
What is the remainder when 741 is divided by 9?
How many numbers among 5001, 6003, 7204, 8400 are divisible by 6?
A perfect square number lies between 1700 and 1800 and is divisible by 9. Find that number and its square root.
Which of the following number is divisible by both 3 and 8?
Which of the following number is neither divisible by 4 nor by 9?
Which of the following number is divisible by both 9 and 11?
