What is the smallest number which leaves remainder 3 when divided by any of the numbers 5, 8 and 9, but leaves no remainder when it is divided by 11?
Given:
Smallest number giving remainder 3 when divided by 5,8 and 9
But no remainder when divided by 11
Formula Used:
LCM is the smallest number when divided by numbers gives remainder zero
Solution:
The LCM of (5,8,9 ) is 360
The number when divided by5,8 and 9 leaves a remainder.
Hence the number is 360+3 = 363
But the number should by divisible by 11 hence the number will be LCM of 363 and 11
But 363 itself is divisible by 11 hence the answer is 363
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