What is the smallest number which leaves remainder 3 when divided by any of the numbers 5, 8 and 9, but leaves no remainder when it is divided by 11?

Correct option is A

Given:

Smallest number giving remainder 3 when divided by 5,8 and 9

But no remainder when divided by 11

Formula Used:

LCM is the smallest number when divided by numbers gives remainder zero

Solution:

The LCM of (5,8,9 ) is 360

The number when divided by5,8 and 9 leaves a remainder.

Hence the number is 360+3 = 363

But the number should by divisible by 11 hence the number will be LCM of 363 and 11

But 363 itself is divisible by 11 hence the answer is 363