What is the smallest natural number that should be added to 1225 such that a remainder of 3 is left when the resulting number is divided by each of the numbers 12,18,21 and 28?

Correct option is A

Given:

The number divided by each of the numbers 12, 18, 21 and 28

Solution:

According to the question,

LCM of (12, 18, 21 and 28) = 7 $$\times$$​ 4 $$\times$$​ 9 = 252

According to the question,

The number should be = 252k + 3,

This number should also be close to 1225

when k = 5, then 252k+3 is:

​$$\Rightarrow 252×5+3 = 1260+3$$​​

= 1263

The number to be added:

1263-1225 = 38

Thus the answer is 38.