What is the median of the following distribution?

Class	110-160	160-210	210-260	260-310	310-360
Frequency	16	15	31	24	38

Correct option is D

Given:
Class Frequency
110-160 16
160-210 15
210-260 31
260-310 24
310-360 38
Formula Used:
Median = $$L + \left( \frac{ \frac{N}{2} - C }{ f } \right) \times h$$​​
Where:
L = Lower boundary of the median class
N = Total frequency
C = Cumulative frequency of the class before the median class
f = Frequency of the median class
h = Class width
Solution:

N = 16 + 15 + 31 + 24 + 38 = 124
​$$\frac N2$$​ = $$\frac{124}{2}$$​= 62
This is the class 210-260, as the cumulative frequency is 62.
L = 210 (lower boundary of the median class)
N = 124
C = 31 (cumulative frequency before the median class)
f = 31 (frequency of the median class)
h = 50 (class width, calculated as 260 - 210)
​$$\text{Median} = 210 + \left( \frac{62 - 31}{31} \right) \times 50\\\text{Median} = 210 + \left( \frac{31}{31} \right) \times 50 = 210 + 50 = 260$$​​