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What is the mean of the following distribution?Marks1327596197No. of Students9557809873
Question

What is the mean of the following distribution?

Marks

13

27

59

61

97

No. of Students

95

57

80

98

73

A.

31

B.

45

C.

51

D.

74

Correct option is C

Formula Used:

Mean = (f×x)f\frac{\sum (f \times x)}{\sum f}​​

where:

f is the frequency (number of students),

x is the value (marks),

Solution:

f × x = (95 × 13) + (57 × 27) + (80 × 59) + (98 × 61) + (73 × 97)

= 1235 + 1539 + 4720 + 5978 + 7081 = 20553

Sum of the frequencies:

∑f  = 95 + 57 + 80 + 98 + 73 = 403

Mean = 20553403=51\frac{20553}{403} =51 ​

Thus, the mean of the distribution is approximately 51

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