What is the mean, median, and mode of the following data?

Class Interval	Frequency
30–40	18
40–50	37
50–60	45
60–70	27
70–80	15
80–90	8

(X̄) (Mean) (M) (Median) (Z) (Mode)

Correct option is D

Mean = Σfx/Σf = 8330/150 = 55.53
Median class = 50–60 => M = 50 + (75–55)/45 ×10 = 54.44
Mode class = 50–60 => Z = 50 + (45–37)/(90–37–27)×10 = 53.08

Hence, Mean = 55.53, Median = 54.44, Mode = 53.08
(Follows relation Mean > Median > Mode → Positively skewed.)