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What is the least number which, when divided by 5, 6, 8 and 10, leaves a remainder of 2 in each case?
Question

What is the least number which, when divided by 5, 6, 8 and 10, leaves a remainder of 2 in each case?

A.

128

B.

122

C.

162

D.

118

Correct option is B


Given: LCM of 5, 6, 8 and 10 = 120
Remainder = 2
Least number will be = 120 + 2 = 122

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