What is the HCF of $$\frac{2}{3},\frac{3}{4}$$, and $$\frac{5}{6}$$​?

Correct option is C

Given:

Fractions: $$\frac{2}{3}, \frac{3}{4}, \frac{5}{6}$$​​

Formula Used:

​$$\text{HCF of fractions} = \frac{\text{HCF of numerators}}{\text{LCM of denominators}}$$​​

Solution:
Numerators: 2, 3, 5
HCF(2, 3, 5) = 1

Denominators: 3, 4, 6
Prime factors:

3 = 3

4 = $$2^2$$​​

6 = 2$$\times 3$$​​
LCM(3, 4, 6) $$= 2^2 \times 3 = 12$$​​

​$$\text{HCF} = \frac{1}{12}$$​