What is the average of all the natural numbers from 1 to 92?

Correct option is C

Given:

1 , 2 , 3 , 4 , 5 …….. , 92

Formula used:

​$$\text{Average} = \frac{\text{Sum of all numbers}}{\text{Total numbers}} ​$$ 

The sum of the first n natural numbers is given by the formula:

​$$\text{Sum} = \frac{n(n + 1)}{2}$$​

Solution :

n = 92 

​$$\text{Sum} = \frac{92(92 + 1)}{2} = \frac{92 \times 93}{2} = 4278$$ 

Then, 

​$$\text{Average} = \frac{\text{Sum}}{\text{Total numbers}} = \frac{4278}{92} = 46.5$$​​

The average of all natural numbers from 1 to 92 is 46.5. 

Thus , the correct answer is option (c) 46.5