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    What is the area of the triangle formed by the coordinate axes and the line​2x+3y=62x+3y=62x+3y=6 ?​
    Question

    What is the area of the triangle formed by the coordinate axes and the line

    2x+3y=62x+3y=6 ?​

    A.

    3 sq. units

    B.

    2 sq. units

    C.

    12 sq. units

    D.

    6 sq. units

    Correct option is A

    Given:

    Line: 2x + 3y = 6

    Formula Used:

    Area of triangle =12×x-intercept×y-intercept \frac{1}{2} \times \text{x-intercept} \times \text{y-intercept}

    Solution:
    Find x-intercept:

    Set y = 0:

    2x = 6

    x = 3

    Find y-intercept:
    Set x = 0:

    3y = 6

    y = 2

    Area =12×3×2=3 square units= \frac{1}{2} \times 3 \times 2 = 3 \text{ square units}

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