What is 6⁰​​​​$$\times$$​ 4² ​$$\times$$​ 2^-4 ?

Correct option is D

Given : 

$$6^0\times4^2\times2^{-4}$$     

Formula Used:

 $$M^0= 1$$   (Any number to the power of 0 is 1.)​

​$$M^{-N}=\frac{1}{M^N}$$

Solution :

=  $$6^0\times4^2\times2^{-4}$$

 = 1$$\times$$ 16 $$\times$$ $$\frac{1}{16}$$

 = 1$$\times$$1$$\times$$1

  = 1

The correct answer is option (d) 1 .