Correct option is D
Information Given:
Vessel P contains 200 liters of a mixture of milk and water in which water is 35%.
y liters of the mixture are taken out, where the quantity of water in y liters is 21 liters.
This y liters are then poured into vessel Q, which already contains y liters of water.
Formulas Used:
Water in mixture = Total Mixture × Percentage of Water/100
Basic Explanation:
Quantity of milk in P = 200×65/100=130
Quantity of water in P = 200×35/100=70
The ratio of milk to water in P = 13:7
y = 21/7×20=60
Quantity of milk in Q = 60×13/20=39 liters
Quantity of water in Q = 60×7/20+60=81 liters
Required difference = 81-39 = 42 liters