A vessel contains 240 liters mixture of milk and water in the ratio of 7 : 5 respectively. If X liters milk is added in the mixture, the milk becomes 80% more than water in final mixture. Find the value of X?

Correct option is A

​Initial quantity of milk = $$\frac{240 \times 7}{12} = 140 \, \text{liters}$$ 

Initial quantity of water = $$\frac{240 \times 5}{12} = 100 \, \text{liters}$$ 

ATQ, $$\frac{140 + X}{100} = \frac{180}{100}$$ 

​​700 + 5X = 900

5X = 200

X = 40

Exam Hall Approach