Two successive discounts on the labelled price of Rs.6000 reduces the sale price to _______________ if the discounts are 10% and 20% successively.

Labelled price = Rs. 6000

Two successive discounts of 10% and 20%

First Discounted Price = Labelled Price ×(1 − First Discount Rate)

Final Sale Price = First Discounted Price ×(1−Second Discount Rate)

First Discounted Price = 6000 × (1−0.10) = 6000 × 0.90 = Rs.5400 

Second Discount:

Final Sale Price = 5400 × (1 − 0.20) = 5400 × 0.80 = Rs.4320 

Thus, the sale price after successive discounts is Rs. 4320.