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Two successive discounts of 30% and 20% was offered on food items. A man paid Rs. 840 for the food item. The bill amount of food item (in Rs. ) is:
Question

Two successive discounts of 30% and 20% was offered on food items. A man paid Rs. 840 for the food item. The bill amount of food item (in Rs. ) is:

A.

2,000

B.

1,200

C.

1,800

D.

1,500

Correct option is D

Given:
First discount = 30%
Second discount = 20%
Final amount paid = Rs. 840
Formula Used:
For successive discounts d₁ and d₂, net price after discounts:
Net price=Original price×(1d1100)×(1d2100) \text{Net price} = \text{Original price} \times \left(1 - \frac{d_1}{100}\right) \times \left(1 - \frac{d_2}{100}\right) ​​
Solution:
Let the original price be x. Then,
840=x×(130100)×(120100) 840=x×70100×80100=x×56100 x=840×10056=1500840 = x \times \left(1 - \frac{30}{100}\right) \times \left(1 - \frac{20}{100}\right) \\\ \\840 = x \times \frac{70}{100} \times \frac{80}{100} = x \times \frac{56}{100} \\\ \\ x = \frac{840 \times 100}{56} = 1500 \\​​
The original bill amount of the food item is Rs. 1500.

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