Two resistances, each of 1000 Ω are connected in parallel across a 200V DC source. then current flowing through the circuit is ________ Amp.

Correct option is C

​$$R_1 = R_2 = 1000\Omega$$, $$V = 200V$$

$$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2}$$

$$\frac{1}{R_{eq}} = \frac{1}{1000} + \frac{1}{1000}$$

$$\frac{1}{R_{eq}} = \frac{2}{1000}$$

$$R_{eq} = \frac{1000}{2} = 500\Omega$$

Ohm’s law formula:

$$I = \frac{V}{R_{eq}}$$​​​​​​​

​$$I = \frac{200}{500}$$

$$I = 0.4 \text{ Amps}$$​​​