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    Two cylindrical candles have unequal heights and diameters. The shorter lasts for 13 hours and the longer for 9 hours. They are lit at the same time a
    Question

    Two cylindrical candles have unequal heights and diameters. The shorter lasts for 13 hours and the longer for 9 hours. They are lit at the same time and after 5 hours their heights are the same. What is the ratio of their original heights?

    A.

    1:2

    B.

    13:18

    C.

    9:13

    D.

    √5:3

    Correct option is B


    Solution:
    Let the original heights of the shorter and longer candles be H₁ and H₂, respectively.
    The burning rate (height burned per hour) for each candle is:
    · Shorter candle: H₁ / 13 per hour
    · Longer candle: H₂ / 9 per hour
    After 5 hours, the remaining heights of both candles are equal:
    H₁ - (5 × H₁ / 13) = H₂ - (5 × H₂ / 9)
    Rearrange the equation:
    H₁ (1 - 5/13) = H₂ (1 - 5/9)
    Multiply the terms:
    H₁ (8/13) = H₂ (4/9)
    Taking the ratio H₁ / H₂:
    (H₁ / H₂) = (4/9) ÷ (8/13)
    (H₁ / H₂) = (4/9) × (13/8)
    (H₁ / H₂) = 52 / 72
    (H₁ / H₂) = 13 / 18
    Final Answer:
    (b) 13:18.

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